.\" Copyright (c) 2012 Apple Inc .\" All rights reserved. .Dd August 16, 2012 .Dt EXP 3 .Os BSD 4 .Sh NAME .Nm exp , .Nm exp2 , .Nm expm1 .Nd exponential functions .Sh SYNOPSIS .Fd #include .Ft float .Fn expf "float x" .Ft double .Fn exp "double x" .Ft long double .Fn expl "long double x" .Ft float .Fn exp2f "float x" .Ft double .Fn exp2 "double x" .Ft long double .Fn exp2l "long double x" .Ft float .Fn expm1f "float x" .Ft double .Fn expm1 "double x" .Ft long double .Fn expm1l "long double x" .Ft float .Fn __exp10f "float x" .Ft double .Fn __exp10 "double x" .Sh DESCRIPTION The .Fn exp function computes e**x, the base-e exponential of .Fa x . .Pp The .Fn exp2 function computes 2**x, the base-2 exponential of .Fa x . .Pp The .Fn __exp10 function computes 10**x; it is not defined in the C standard, and therefore may not be portable to other platforms. It is provided as a convenience to programmers because it may be computed more efficiently than pow(10,x). .Pp If .Fa x is nearly zero, then the common expression .Fn exp "x" - 1.0 will suffer from catastrophic cancellation and the result will have little or no precision. The .Fn expm1 function provides an alternative means to do this calculation without the risk of significant loss of precision. If you find yourself using this function, you are likely to also be interested in the .Fn log1p function. .Pp Note that computations numerically equivalent to .Fn exp "x" - 1.0 are often hidden in more complicated expressions; some amount of algebraic manipulation may be necessary to take advantage of the .Fn expm1 function. Consider the following example, abstracted from a developer's actual production code in a bug report: .Bd -literal -offset indent double z = exp(-x/y)*(x*x/y/y + 2*x/y + 2) - 2 .Ed .Pp When .Fa x is small relative to .Fa y , this expression is approximately equal to: .Bd -literal -offset indent double z = 2*(exp(-x/y) - 1) .Ed .Pp and all precision of the result is lost in the computation due to catastrophic cancellation. The developer was aware that they were losing precision, but didn't know what to do about it. To remedy the situation, we do a little algebra and re-write the expression to take advantage of the .Fn expm1 function: .Bd -literal -offset indent exp(-x/y)*(x*x/y/y + 2*x/y + 2) - 2 = (2*exp(-x/y) - 2) + exp(-x/y)*((x*x)/(y*y) + 2*x/y) .Ed .Pp This transformation allows the result to be computed to a high degree of accuracy as follows: .Bd -literal -offset indent const double r = x/y; const double emrm1 = expm1(-r); double z = 2.0*emrm1 + (1.0 + emrm1)*(2.0 + r)*r; .Ed .Pp It is not always easy to spot such opportunities for improvement; if an expression involving .Fn exp seems to be suffering from an undue loss of accuracy, try a few simple algebraic operations to see if you can identify a factor with the form .Fn exp "x" - 1.0, and substitute .Fn expm1 "x" in its place. .Sh SPECIAL VALUES .Fn exp "±0" and .Fn exp2 "±0" return 1. .Pp .Fn exp "-infinity" and .Fn exp2 "-infinity" return +0. .Pp .Fn exp "+infinity" and .Fn exp2 "+infinity" return +infinity. .Pp .Fn expm1 "±0" returns ±0. .Pp .Fn expm1 "-infinity" returns -1. .Pp .Fn expm1 "+infinity" returns +infinity. .Pp For all these functions, a range error occurs if the magnitude of x is too large. .Sh VECTOR OPERATIONS If you need to apply the .Fn exp functions to SIMD vectors or arrays, using the following functions provided by the Accelerate.framework may give significantly better performance: .Pp .Fd #include .Pp .Ft vFloat .Fn vexpf "vFloat x" ; .br .Ft vFloat .Fn vexpm1f "vFloat x" ; .br .Ft void .Fn vvexpf "float *y" "const float *x" "const int *n" ; .br .Ft void .Fn vvexp "double *y" "const double *x" "const int *n" ; .br .Ft void .Fn vvexpm1f "float *y" "const float *x" "const int *n" ; .br .Ft void .Fn vvexpm1 "double *y" "const double *x" "const int *n" ; .br .Ft void .Fn vvexp2f "float *y" "const float *x" "const int *n" ; .br .Ft void .Fn vvexp2 "double *y" "const double *x" "const int *n" ; .Sh SEE ALSO .Xr log 3 , .Xr pow 3 , .Xr math 3 .Sh STANDARDS The .Fn exp , .Fn exp2 , and .Fn expm1 functions conform to ISO/IEC 9899:2011.